Hvis der er 5 ved bordet er der 120 muligheder (5*4*3*2*1):
ABCDE ABCED ABDCE ABDEC ABECD ABEDC ACBDE ACBED ACDBE ACDEB ACEBD ACEDB
ADBCE ADBEC ADCBE ADCEB ADEBC ADECB AEBCD AEBDC AECBD AECDB AEDBC AEDCB
BACDE BACED BADCE BADEC BAECD BAEDC BCADE BCAED BCDAE BCDEA BCEAD BCEDA
BDACE BDAEC BDCAE BDCEA BDEAC BDECA BEACD BEADC BECAD BECDA BEDAC BEDCA
CABDE CABED CADBE CADEB CAEBD CAEDB CBADE CBAED CBDAE CBDEA CBEAD CBEDA
CDABE CDAEB CDBAE CDBEA CDEAB CDEBA CEABD CEADB CEBAD CEBDA CEDAB CEDBA
DABCE DABEC DACBE DACEB DAEBC DAECB DBACE DBAEC DBCAE DBCEA DBEAC DBECA
DCABE DCAEB DCBAE DCBEA DCEAB DCEBA DEABC DEACB DEBAC DEBCA DECAB DECBA
EABCD EABDC EACBD EACDB EADBC EADCB EBACD EBADC EBCAD EBCDA EBDAC EBDCA
ECABD ECADB ECBAD ECBDA ECDAB ECDBA EDABC EDACB EDBAC EDBCA EDCAB EDCBA
Hvis der er 12 er der 479001600 muligheder, men dem gider jeg ikke skrive ned